有以下程序 #include <stdio.h> #include <string.h> void fun(char *s[], int n) { char *t; int i, j; for (i=0; i<n-1; i++) for (j=i+1; j<n; j++) if (strlen(s[i]) > strlen(s[j])) { t = s[i]; s[i] = s[j]; s[j] = t; } } main() { char *ss[]={"bcc","bbcc","xy", "aaaacc", "aabcc"}; fun(ss, 5); printf("%s,%s\n", ss[0],ss[4]); } 程序的运行结果是

有以下程序 #include #include void fun(char s[], int n) { char t; int i, j; for (i=0; i strlen(s[j])) { t = s[i]; s[i] = s[j]; s[j] = t; } } main() { char *ss[]={"bcc","bbcc","xy", "aaaacc", "aabcc"}; fun(ss, 5); printf("%s,%s\n", ss[0],ss[4]); } 程序的运行结果是

A.aaaacc,xy
B.xy,aaaacc
C.bcc,aabcc
D.aabcc,bcc

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参考答案：B

解析：

【解析】函数fun(char s[ ],int n)的功能是对字符串数组的元素按照字符串的长度从小到大排序，在主函数中执行fun(ss,5)语句后，*ss[]={"xy","bcc","bbcc","aabcc","aaaacc"}，ss[0],ss[4]的输出结果为xy,aaaacc。因此B选项正确。

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有以下程序 #include #include void fun(char *s[], int n) { char *t; int i, j; for (i=0; i strlen(s[j])) { t = s[i]; s[i] = s[j]; s[j] = t; } } main() { char *ss[]={"bcc","bbcc","xy", "aaaacc", "aabcc"}; fun(ss, 5); printf("%s,%s\n", ss[0],ss[4]); } 程序的运行结果是

有以下程序 #include #include void fun(char s[], int n) { char t; int i, j; for (i=0; i strlen(s[j])) { t = s[i]; s[i] = s[j]; s[j] = t; } } main() { char *ss[]={"bcc","bbcc","xy", "aaaacc", "aabcc"}; fun(ss, 5); printf("%s,%s\n", ss[0],ss[4]); } 程序的运行结果是